Matematika hitung jumlah deret geometri 3+6+12+...+192​

jedschadenulv – June 01, 2023

hitung jumlah deret geometri 3+6+12+...+192​

Diket: a = 3

r = 6/3 = 2

192 = ar^n-1

192 = 3×2^n-1

192/3 = 2^n-1

64 = 2^n-1

n+1 = √64

n+1 = 8

n = 7

S7 = a (r^n - 1)/r - 1

S7 = 3 (2⁷ - 1) / 2 - 1

S7 = 3 (128 - 1)

S7 = 3 (127)

S7 = 381